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如何将电压TDR转换为阻抗TDR

TDR、阻抗访问量:1时间:2022-07-15

根据下面的电路,我已经建立了基于电压的TDR图。

然后我去了ADS TDR模拟,按照手册构建了下面的电路。

在ADS电路中,他们说,阻抗=V/I=V/(delta(V)/R)=V*R/Voltage_drop_over_R

我看不出这个公式的逻辑。

为什么测量传输线左侧的阻抗随时间变化意味着它在传输线的某个位置的阻抗?

你公式中的符号都没有出现在两个原理图中,所以我不知道它们指的是什么。然而,如果V是任何支路中的两端元件A上的电压降,R是同一支路中的电阻,I是(R上的电压降)/R,那么V/I当然是A处的阻抗(A上的电压除以通过A的电流)。这并没有告诉我们电路中其他地方的阻抗。

对于动态信号,如太阳能电池板和微波,我们有时会发现欧姆定律对于增量电阻以及最大功率定理和平均阻抗是有用的。

对于太阳能电池板的MPPT工作点来说,类似但又不同。

这方面的另一个远亲是负载调节,如果我们知道一个电源在某个负载R下有1%的负载调节电压误差,我们可以暗示源阻抗必须是R的1%。

原文:

How can I convert from voltage TDR into impedance TDR

Based on the circuit below I have built the voltage based TDR diagram.

Then I went to the ADS TDR simulation and constructed by the manual the circuit below.

In the ADS circuit they say that IMPEDANCE=V/I=V/(delta(V)/R)=V*R/Voltage_drop_over_R

I can't see the logic of this formula.

Why does measuring impedance on the left side of the transmission line over time means its the impedance at some location in the transmission line?

None of the symbols in your formula appear in either schematic, so I don’t know what they refer to. However, if V is the voltage drop across a 2-terminal component A in any branch, R is a resistor in the same branch, and I is (voltage drop across R)/R, then it is certainly true that V/I is the impedance at A (the voltage across A divided by the current through A). This does not tell us the impedance anywhere else in the circuit.

For dynamic signals such as Solar Panels and microwave, we sometimes find Ohm's law is useful for incremental resistance as well as the max power theorem and for the mean impedance.

Similarily yet different for a Solar Panel's MPPT operating point.

Another distant relative of this is Load Regulation, where if we know a power supply as 1% load regulation voltage error at some load R , we can imply that the source impedance must be 1% of R.

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